English: Solutions to Apollonius' problem are related by circle inversion. Here, the three given circles are shown in black, with their radical center shown as a large orange point, whereas the two solutions are shown as pink circles. The orange orthogonal circle centered on the radical center intersects the three given circles perpendicularly (orthogonally), so that the given circles map to themselves under inversion in the orange circle. The two pink circles map to each other, as do their corresponding tangent points (blue) with the given circles. The green lines also map to themselves, since they pass through the center of inversion.
to share – to copy, distribute and transmit the work
to remix – to adapt the work
Under the following conditions:
attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use.
share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible license as the original.
Permission is granted to copy, distribute and/or modify this document under the terms of the GNU Free Documentation License, Version 1.2 or any later version published by the Free Software Foundation; with no Invariant Sections, no Front-Cover Texts, and no Back-Cover Texts. A copy of the license is included in the section entitled GNU Free Documentation License.http://www.gnu.org/copyleft/fdl.htmlGFDLGNU Free Documentation Licensetruetrue
You may select the license of your choice.
Captions
Add a one-line explanation of what this file represents
{{Information |Description={{en|1=Solutions to Apollonius' problem are related by circle inversion. Here, the three given circles are shown in black, with their radical center shown as a large orange point, whereas the two solutions are shown as pink cir